conversion of nanograms to micromoles

I need to convert a 1683.2 ng/ul of a primer to nanomoles/ul.please help

[JohnS]

Just divide by the molecular weight, which is also the molar mass in g/mol.

5-aminosalicylic acid (5-ASA): 4.3 µmol/L, Pl.convert to nanogram/mL.

I´d to know how to convert .04 micromoles/L of progesterone (M.W. 314.4668) to ng/ml. thanks alot for your time.

[JohnS]

Originally Posted by heliozoo

I´d to know how to convert .04 micromoles/L of progesterone (M.W. 314.4668) to ng/ml. thanks alot for your time.

Thanks for finding the MW. It is also the molar mass in grams per mole. This simplifies your problem to prefix manipulation

0.04 µmol/L x 314.4668 g/mol = 12.579 µg/L
Since 1000 ng = 1 µg, and 1000 mL = 1L, the two factors of 1000 will cancel, and it is also 12.579 ng/mL.

I'm trying to convert 3.10 umol/L of selenium to ng/ml. Molar mass of selenium is 78.96g/mol. As I understand from previous calculations that should equate to 244.78 ng/ml. Unfortunately this falls outside the reference range while the 3.10umol/L falls well within the reference range. So i just wanted to be sure I was doing my calculations correctly....

[JohnS]

Originally Posted by Unregistered

I'm trying to convert 3.10 umol/L of selenium to ng/ml. Molar mass of selenium is 78.96g/mol. As I understand from previous calculations that should equate to 244.78 ng/ml. Unfortunately this falls outside the reference range while the 3.10umol/L falls well within the reference range. So i just wanted to be sure I was doing my calculations correctly....

Yes, you did it right:
3.10 µmol/L x 78.96 g/mol = 244.78 µg/L (or ng/mL)
(probably should be rounded to 245 µg/L)

You might check the desired units, though. Many blood tests stated as mass/volume are stated per deciliter (dL, equal to 0.1 L or 100 mL). The above would be 24.5 µg/dL.

[John]

Can some one please tell me how to achieve a final concentration of 100 pM ACTH F.W. 2933, in a final volume of 10 ml? I have an aliquot stock of ACTH at a concentration of 100 ng/µl?

[Mrs X]

Originally Posted by John

Can some one please tell me how to achieve a final concentration of 100 pM ACTH F.W. 2933, in a final volume of 10 ml? I have an aliquot stock of ACTH at a concentration of 100 ng/µl?

is F.W. the same as the molecular weight?

If so, you want 10mL of concentration 100pM (picomoles per litre).

The weight you need is 10(mL)/1000(mL) x 2933(pg) x 100(pM) = 2933pg in 10mL (or 2.933ng in 10mL).

This requires 0.02933µL of your stock.

You probably should do a 1 in 100 dilution on your stock to be able to reliably get 2.933ng. Even at a 1:100 dilution, this is still only 2.933µL diluted stock required.

Can someone please tell me how to convert nanograms/gram (lipid weight) to uM?

I would like to convert 188 ng/g to uM. The substance has a MW of 641.7 gram/mole.