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#1
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This is so simple, ...but I can't nail it!!
What is the conversion from Db to Watt?
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#2
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0 decibel is equal to 1 picowatt per square meter. This corresponds to the faintest sound that can be detected by a person with good hearing.
A sound of 10 decibels means it is perceived as 10 times louder than 0 decibels. Since decibels is a logarithmic unit of perceptive sound, I do not think there is a direct conversion between it and power. I have seen conversions between decibel and power/area and between decibel and pressure, but I am fairly sure it would depend on the specific circumstances. Perhaps someone in the audio field could shed more light on the subject. |
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#3
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This would be power conversion in RF terms. ie., 20Db @ 850Mhz. There is a power value in Watts. As in, so many Db equals so many watts.
I'm not clear on the conversion??? |
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#4
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#5
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Quote:
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#6
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dbm = 10^((WATTS - 30)/10)
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#7
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30db = 1 watt (1000 mw)
27db = .5 watts (500mw) for each 3 db gain or loss it doubles or halves. 33db = 2 watts (2000mw) 36db = 4 watts (4000mw) 24db = .25watts (250mw) |
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#8
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Forgot the formula!
Converting db to mw and mw to db db=10*log(mw) mw=anti-log(db/10) |
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#9
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Quote:
60 dbm -30= 30 Divide by 10 = 3 log of 3 = 1000 50 dbm -30 = 20 Divide by 10 = 2 log of 2 = 100 +60 dbm =1000 watts +50 dbm = 100 watts each 3 db is twice or 1/2 of starting power |
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#10
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I am trying to convert dBm to Watts and none of the formula described so far work.
I have a reliable conversion from watts to dbm, but I cant reverse the situation, the formulas here don't reverse the result. I am trying to do this in Excel, it is being used in a calculator for a Wifi Link budget. This is the current Watts -> dBm (works) =10*LOG10(D8/ 0.001) and in its current form, dBm -> Watts (doesn't work) =LOG((D9-30)/10) 'D8' (watts) and 'D9' (dBm) accept input from a user =) If anyone can help, please email me [..guest link removed..] |
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