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#61
07-24-2011, 07:52 PM
 Unregistered Guest Posts: n/a
Re: Find the radius from a chord

Thanks Robert. Your suggestion solved my problem.
#62
08-17-2011, 05:59 AM
 Unregistered Guest Posts: n/a
Re: Find the radius from a chord

I have the Delta Angle and the Cord Length

#63
08-17-2011, 06:19 AM
 JohnS Double Ultimate Supreme Member Join Date: Dec 2007 Location: SE Michigan, USA Posts: 8,707 Rep Power: 17
Re: Find the radius from a chord

Quote:
 Originally Posted by Unregistered I have the Delta Angle and the Cord Length I need the Radius
You have to use half the chord length and half the central angle

R = 0.5*c/sin(0.5*theta)
#64
09-24-2011, 11:42 AM
 maha Junior Member Join Date: Sep 2011 Posts: 2 Rep Power: 0
Re: Find the radius from a chord

please i would like to know how i can measure the radius knowing the length of the chord xz and the lenght of the arc??
#65
09-24-2011, 11:49 AM
 maha Junior Member Join Date: Sep 2011 Posts: 2 Rep Power: 0
Re: Find the radius from a chord

#66
09-24-2011, 01:08 PM
 JohnS Double Ultimate Supreme Member Join Date: Dec 2007 Location: SE Michigan, USA Posts: 8,707 Rep Power: 17
Re: Find the radius from a chord

Quote:
 Originally Posted by maha please i would like to know how i can measure the radius knowing the length of the chord xz and the lenght of the arc??
see post #22
#67
11-07-2011, 01:39 AM
 NABUNWA GERALD Guest Posts: n/a
Re: Find the radius from a chord

formula to find the length when given only the chord
#68
11-29-2011, 03:15 PM
 Unregistered Guest Posts: n/a
Re: Find the radius from a chord

I just had a great time solving this one. It's a fun one!
If the chord length is 2b, and the sagitta/height is s and the apothem (radius minus the height) is a and the radius is c, then pythagoras gives

(1) a^2+b^2=c^2
and since the radius is the sum of apothem and the sagitta:
(2) c=a+s

then solve pythagoras for b^2 and sub (2) into it
(3) b^2=(a+s)^2-a^2
(4) b^2=a^2+2as+s^2-a^2
(5) b^2=2as+s^2

solve for a:
(6) a=(b^2-s^2)/(2s)

sub (6) into (2)
(7) c=(b^2-s^2)/2s +s
(8) c= (b^2-s^2+2s^2)/2s
(9) c= (b^2+s^2)/(2s)

as long as you remember that b is HALF the chord length.
#69
02-20-2012, 09:43 PM
 Krystal Guest Posts: n/a

it is given that ab is the diameter of a circle and o is its centre. ab bisects the chord cd at e such that ce=ed= 8 cm and eb= 4cm. find the radius.
#70
02-26-2012, 11:41 AM
 alexuslara Junior Member Join Date: Feb 2012 Posts: 2 Rep Power: 0
Re: Find the radius from a chord

how about calculating the area of a segment when the only information available are the length of the cord and the hight of the segment? (in your figure it would be "C" and "M"). Thanks, Gabriel

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