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#1
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how to convert 15 mole percent of styrene (MW=104 g/mol) to weight percent, if we know the other monomer M (MW= 54 g/mol) is 85 mole % in the polymer?
Is this info enough or dowe need more data to get the conversion? |
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#2
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Quote:
The weights of the mixture components are 15 moles*104 g/mol = 1560 g styrene, and 85 moles * 54 g/mole = 4590 g of the other monomer. The total mixture is 1560 g + 4590 g = 6150 g, and the weight ratio of styrene to total mixture is 1560 g/6150 g = 25.4% Since we postulated 100 moles, and total weight is 6150 g, the average molar mass of the mixture is 61.5 g/mol, and you can get the same answer as 15% * 104 g/mol / 61.5 g/mol (this "average" approach is often used for pollutants mixed in air) |
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#3
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John thanks a lot for the explanation. It seems very simple now.
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#4
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5mol percent of 6.26grm of Bi2O3
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#5
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I want to know how to calculate 10 mol % of CuO
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#6
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I want to know how to calculate 10 mol % of para toluene sulphonic acid
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#7
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the mole%of sodium hydroxide weight of 100gm.
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#8
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Approximate molar mass is (23 + 16 + 1) g/mol or 40 g/mol
100 g is about 2.5 mol. No percent involved. If it is pure sodium hydroxide then it is 100% sodium hydroxide whether by weight, volume, or molar ratios. Percent and parts per million are for mixtures of one thing in another thing. |
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#9
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What if I am given a molar flow rate (300mol/h) for a gas stream but am given %wt percents for each species in the stream? How can these be converted to mol%?
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#10
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Quote:
If they are percent by weight, divide by the molecular weight of the species and multiply by the (average) molecular weight of the mixture. |
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