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#1
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I have 4.4% of Fe2O3 (as measured by XRF) can anybody help me to convert it into Fe in ppm or ppb.
Thanks Regards Farooq |
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#2
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#3
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molecular weight Fe2O3=159.69g
molecular weight Fe=55.845g 4.4%=44000 ppm 159.69----------55.845*2 g Fe 44000-----------x x=44000*55.845*2/159.69 x=30774.38 ppm Fe |
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#4
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Hi Elena, sometimes questions like this have been asked before, but it has turned out that the questioner has a lab result from a sample that has been dissolved up, and run against a set of standards. This is why we can always do with a bit more info.
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#5
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#6
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#7
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Hi Gents,
To convert Fe2O3 to Fe divide by 1.4298. To convert % to PPM multiply by 10000. It is that simple. He is obviously analysing iron ore by XRF fusion or PP. |
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#8
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I mean how you work out to get 1.4298 Thanks |
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#9
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I mean how you work out to get 1.4298 can you email it to aj4u2000@hotmail.com ...I don't know how to get the answer back from this site. Thanks |
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#10
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Atomic weight Fe = 55.847g/mol, atomic weight oxygen = 15.999g/mol 2 x 55.847 + 3 x 15.999 = 159.691grams per mole (g/mol) The iron proportion is (2 x 55.847)/159.691 = 0.6994. The reciprocal is 1.430, so you can either divide by 1.430 or multiply by 0.6994 to get the weight of iron in iron oxide. Note however, iron oxide is rarely pure Fe2O3, there are usually other oxide species and hydroxides present. |
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