g/kwh to gal/h

may i know in the previous calculation whether you consider the efficiency already? i looks the genset has a round 50% efficiency.

how to compute kwh/liter?

[JohnS]

Originally Posted by Unregistered

how to compute kwh/liter?

Measure the engine's power output (kilowatts) and fuel flow (liters per hour). Divide.

It varies with the heat content of the fuel and the efficiency of the engine. For a particular engine and fuel, it varies considerably with torque and rpm (the plot is called an engine map, and shows brake specific fuel consumption contours vs torque and rpm).

There are 453.6 grams per pound.

230 g/kw hr = ( 230/453.6 ) lb/kw hr ~= 0.507 lbm/kw-hr

There are approximately 7.4 pounds / gallon for #2 D diesel fuel

0.507 lbm/kw-hr / 7.4 lbm / gal ~= 0.069 gal / kw-hr

If 60 kw, then hourly fuel oil usage ~= 0.069 x 60 kw ( kw drops out ) = 4.11 gal/hr

The reciprocal of "gal/kw-hr" i.e. "kw-hr/ gal" is a more used term of electric generator efficiency using diesel engines.

In this case 1 / 0.069 ~= 14.5 kw-hr / gal. a very competitive level.

each KWh will consume 0.31 liters for small machines ( under 50 KVA ) , 0.26 to 0.28 for mid machines under 250 KVA , and 0.252 litres for large machines , for DS#2 fuel

If a 2650 kW Main Engine has a fuel consumption of 210.2 g/kWh at full load. How much it will be at t/h ? Thanks

[JohnS]

Originally Posted by Unregistered

If a 2650 kW Main Engine has a fuel consumption of 210.2 g/kWh at full load. How much it will be at t/h ? Thanks

210.2 g/kWh x 2650 kW x 1 t/10^6 g = 0.557 t/h

Originally Posted by JohnS

210.2 g/kWh x 2650 kW x 1 t/10^6 g = 0.557 t/h

Thank you....