g/kwh to gal/h

I am trying to compare fuel consumption ratings on Diesel electric generators
The american ones show gals per hour of consumption at 50% load 75% load & 100% load which is what I am familiar with.
All the other generator sets are rated by g/kwh which I think is grams per Kilowatt hour?
What I'm having trouble with is a gram is a weight not a volume? Do I multiply the total kilowatt hours which in this case is 60kw x the grams per hour(in this case 230) 60x230=13,800 grams
Do I have to figure out what a gal of diesel fuel wieghs? and the convert the grams to weight?

Any help would be great.
Thanks A+

[Robert Fogt]

I found a chart that lists diesel fuel oil 20 to 60 at 15º C as having a density between 820 and 950 kilograms/cubic meter (which is the same as gram/liter).

If you know how many grams of fuel you have:
grams / 820 gram/liter = liters

If you know how many liters of fuel you have:
liters * 820 gram/liter = grams

Now just convert liters to gallons, or gallons to liters first.
1 gallon [US, liquid] = 3.7854118 liter

Also you may wish to use a mid value between 820 and 950 for the density, or work the formula out for both 820 and 950 to get the range.

I would to convert a 213 g/kwh to l/h

i would like to know how to convert from g/kWh to l/h ?? must i change it to other forms before i could proceed to liter/hour..??

thank you so much

[JohnS]

Originally Posted by Robert Fogt

I found a chart that lists diesel fuel oil 20 to 60 at 15º C as having a density between 820 and 950 kilograms/cubic meter (which is the same as gram/liter).

If you know how many grams of fuel you have:
grams / 820 gram/liter = liters

If you know how many liters of fuel you have:
liters * 820 gram/liter = grams

Now just convert liters to gallons, or gallons to liters first.
1 gallon [US, liquid] = 3.7854118 liter

Also you may wish to use a mid value between 820 and 950 for the density, or work the formula out for both 820 and 950 to get the range.

I think that range is combining diesel and fuel oil. 950 g/L is a pretty heavy fuel oil, needs heating to keep it flowing. #1 diesel (winter) would be at the low end of your range, maybe even a little lower, #2 diesel maybe 0.83-0.85, There is lot and refinery variation

Originally Posted by Robert Fogt

I found a chart that lists diesel fuel oil 20 to 60 at 15º C as having a density between 820 and 950 kilograms/cubic meter (which is the same as gram/liter).

If you know how many grams of fuel you have:
grams / 820 gram/liter = liters

If you know how many liters of fuel you have:
liters * 820 gram/liter = grams

Now just convert liters to gallons, or gallons to liters first.
1 gallon [US, liquid] = 3.7854118 liter

Also you may wish to use a mid value between 820 and 950 for the density, or work the formula out for both 820 and 950 to get the range.

The data that I have is

Fuel consumption at full load: appr. 213 [g/kWh]

Now : How much fuel is the equipment actually consuming per hour ?

For your info : It is an AC Generator designed to give 200 V AC power @ 400 HZ frequency and power Factor of 180 KVA.

Originally Posted by Robert Fogt

I found a chart that lists diesel fuel oil 20 to 60 at 15º C as having a density between 820 and 950 kilograms/cubic meter (which is the same as gram/liter).

If you know how many grams of fuel you have:
grams / 820 gram/liter = liters

If you know how many liters of fuel you have:
liters * 820 gram/liter = grams

Now just convert liters to gallons, or gallons to liters first.
1 gallon [US, liquid] = 3.7854118 liter

Also you may wish to use a mid value between 820 and 950 for the density, or work the formula out for both 820 and 950 to get the range.

Fuel consumption at full load: appr. 213 [g/kWh]

Now...what will be amount of fuel consumed per hour ?

This is for a 180 KVA generator supplying 200 V AC @ 400 HZ .

Please help me sort this out

[JohnS]

Originally Posted by euphoria_82

Fuel consumption at full load: appr. 213 [g/kWh]

Now...what will be amount of fuel consumed per hour ?

This is for a 180 KVA generator supplying 200 V AC @ 400 HZ .

Please help me sort this out

Lets avoid issues of the "power factor" of the load, and assume power factor is 1, so 180 KVA = 180 kW.

213 g/kWh x 180 kW = 38340 g/h or 38.340 kg/h
A liter of diesel fuel is about 0.85 kg, so 45.1 L/h or 11.9 US gallons per hour at full load. If generator is not putting out full load, consumption will be less, but not linearly with load (it still consumes fuel just to spin, even if no load is connected.)

Originally Posted by JohnS

Lets avoid issues of the "power factor" of the load, and assume power factor is 1, so 180 KVA = 180 kW.

213 g/kWh x 180 kW = 38340 g/h or 38.340 kg/h
A liter of diesel fuel is about 0.85 kg, so 45.1 L/h or 11.9 US gallons per hour at full load. If generator is not putting out full load, consumption will be less, but not linearly with load (it still consumes fuel just to spin, even if no load is connected.)

Thanks a lot John..You made it really simple.

I applied the same logic to calculate the consumption for a Air Conditioning Unit (115 Tons) that had "Specific fuel consumption at maximum torque : 200 g/KWh.". Here the output of the engine was expressed in BHP. I simply converted BHP to KW (Mulitplied BHP by 0.7457 to get KW) and then got the calculation done as you mentioned

Thanks all the way from India

If a 500 kW diesel generator has a fuel consumption of 208 g/kWh at full load. How much it will be at 50% and 25% load? Thanks