PDA

View Full Version : how to convert amps into kwh usage

unone
09-22-2007, 02:11 PM
i need to convert ampere of usage into kwh

gubment_cheez
09-22-2007, 07:38 PM
an ampere is an instantaneous measurement, while KWH is a measurement of watts (in this case, kilowatts) over time. it's like converting linear feet to cubic feet, you just can't do it

Unregistered
02-19-2008, 05:39 AM
converting amps to kwh requires multiple equasions, for example i will show the process for converting the amps used by a 100 watt bulb in a 115/120 volt powered circuit.
E=IxR states that volts are equivilent to amps X watts
So inversly volts divided by watts = amps
in this case 120 volts divided by 100 watts =1.2 amps
that given and adding that kwh=1000 watts used for 1 hr
so inversly a 1.2 amp load used continuosly for 1 hr = 100watt hours or 0.10kwh

I hope that helps

Unregistered
03-29-2008, 03:40 AM
i need to convert ampere of usage into kwh
I have a motor drawing 4.7 amps at 120V. What is my kwh usage

JohnS
03-29-2008, 09:55 AM
I have a motor drawing 4.7 amps at 120V. What is my kwh usage

It depends on how long it runs. Instantaneous power is 4.7 A x 120 V = 564 W or 0.564 kW.

Therefore it uses 0.564 kWh/h. Multiply by hours operated and you will have your answer.

Aayush
03-08-2009, 08:02 AM
I think JohnS method should be helpful to you...

Unregistered
03-24-2009, 01:42 PM
an ampere is an instantaneous measurement, while KWH is a measurement of watts (in this case, kilowatts) over time. it's like converting linear feet to cubic feet, you just can't do it

KWH is a measure of energy, not power. it is kilowatts* hours.

Unregistered
08-16-2009, 07:51 AM
if i reduce the amps rate by an energy saver will kwh will reduce

JohnS
08-16-2009, 08:33 AM
if i reduce the amps rate by an energy saver will kwh will reduce

kWh = volts*amps*hours/1000

If you reduce the amps, the energy consumed will be less UNLESS it runs longer (for example, something controlled by a thermostat that runs until it reaches a temperature.)

Picky note: above is only correct if current is in phase with voltage and constant. If current varies or turns on and off with a switch (thermostat) it is a little more complex.

wengg@kores-india.com
08-17-2009, 03:32 AM
i need to convert ampere of usage into kwh. one main feeder is loading 1000 amp. please let me know with formula how much kwh consumption.

JohnS
08-17-2009, 04:28 AM
. one main feeder is loading 1000 amp. please let me know with formula how much kwh consumption.

What is the voltage? Is it single phase or three phase? How many hours does it run? What is the power factor? There is no way to answer the question without that additional information.

Unregistered
08-20-2009, 09:21 AM
How do I convert kwh to kwa rating? Example: 7280Kwh peak 480v 3phase.

Mel
08-21-2009, 08:14 AM
i need to convert ampere of usage into kwh

I want to know what my consumption of KWh is for a baler machine, this is the data:
10hp
208-230/460 (3 phase, 230v)
28-26amp
1725 RPM
60HZ
Thank you.

JohnS
08-21-2009, 08:53 AM
I want to know what my consumption of KWh is for a baler machine, this is the data:
10hp
208-230/460 (3 phase, 230v)
28-26amp
1725 RPM
60HZ
Thank you.

It depends on how many kilowatts it draws and how many hours it runs (just multiply them together).

In the electrical data, is there any mention of "power factor?" I ask because the numbers don't agree well. If it is 10 HP output, that is 7.46 kW output power. Since no machine is 100% rfficient, I would expect it to draw around 9-10 kW to out put that, based on typical efficiencies.

Edit: I started out assuming the 230 V was line to neutral. I'm pretty sure it is line to line, and needs to be divided by square root of 3.

If I multiply the volt*ampere rating, I get 3*230 V*26 A = 17940 VA = 17.94 kVA. However, if I assume the voltage is line-to-line and divide by the square root of 3, I get 10.4 kVA. If the power factor is close to 1, then it is also 10.4 kW. Just multiply by the hours runs for kilowatt*hours.

Unregistered
08-27-2009, 03:09 AM
i need to convert ampere of usage into kwh

i want to convert 10 amps of usage into kwh

Unregistered
10-19-2009, 07:24 PM
i need to convert ampere of usage into kwh

Unregistered
10-20-2009, 09:52 AM
can any body help me to get the right generator for my crusher plant , i had in section A ( 9 morors , total of 240kw, total of 490amp, volt 380, 3 phas.) section B ( 14 motors ,total 510kw,967amp,volt 380,3phas)
thanks for you.

gubment_cheez
10-21-2009, 04:23 PM
can any body help me to get the right generator for my crusher plant , i had in section A ( 9 morors , total of 240kw, total of 490amp, volt 380, 3 phas.) section B ( 14 motors ,total 510kw,967amp,volt 380,3phas)
thanks for you.
what are the surge ratings for each motor, or section? (every motor draws more current than normal until it is up to speed, causing an electrical surge) once you have this, you can find a generator that matches or exceeds that surge rating.

jackchew
11-18-2009, 11:02 PM
can some one tell me 1am = how many kwh for 240 voltage.

JohnS
11-19-2009, 03:00 AM
can some one tell me 1am = how many kwh for 240 voltage.

1 A x 240 V = 240 W = 0.24 kW
In 1 hour, it will consume 0.24 kWh,
in 10 h, 2.4 kWh
In 720 h (roughly a month), 173 kWh, if run continuously.

Unregistered
11-21-2009, 12:46 AM
Example:

1HP (0.75KW) 400V/I@max=1.8A Eff=0.76, PF=0.80 (Assume without inverter)

may i know how to get the kwh for a 415V? if we just assume with a full load amp.

is there any relevant between power factor & kwh? is that true that, increase of PF and decrease of amp actually provide the same kwh? unless do certain setting on the inverter?

Thanks~

Unregistered
03-22-2010, 08:21 AM
i need to convert ampere of usage into kwh
i want to know how many kwh my r.v. is useing,it is useing 10 amp of power?

Unregistered
03-24-2010, 12:40 PM
an ampere is an instantaneous measurement, while KWH is a measurement of watts (in this case, kilowatts) over time. it's like converting linear feet to cubic feet, you just can't do it

Actually an Ampere is 1 Coulomb over 1 second. Amps are sometimes abreviated as As to avoid confusion with Amp Hours (Ah) which are 60*60 times greater.

JohnS
03-24-2010, 02:35 PM
Actually an Ampere is 1 Coulomb over 1 second. Amps are sometimes abreviated as As to avoid confusion with Amp Hours (Ah) which are 60*60 times greater.

Amperes are never"abbreviated as "As" as the proper SI symbol is "A."
"As" would symbolize an ampere-second, better known as a coulomb.
1 Ah = 3600 C.

Unregistered
04-26-2010, 01:50 PM
If I have a split A/C unit that runs on 4amps, 220V, 60 hertz,single phase, SEER 17 how many kwh will it use if I run it for 8 hours?

JohnS
04-26-2010, 02:26 PM
If I have a split A/C unit that runs on 4amps, 220V, 60 hertz,single phase, SEER 17 how many kwh will it use if I run it for 8 hours?

If the compressor runs continuouslt
220 V x 4 A x 8 h x 1 kW/1000 W = 7.04 kWh

If the thermostat cycles the compressor on and off, that will be reduced roughly by to the percentage duty cycle.

Unregistered
05-04-2010, 04:22 AM
It depends on how long it runs. Instantaneous power is 4.7 A x 120 V = 564 W or 0.564 kW.

Therefore it uses 0.564 kWh/h. Multiply by hours operated and you will have your answer.

Ohm`s law is for resistive loads, which cann`t applies to neither inductive or capacitive loads, such as motors, transformers

JohnS
05-04-2010, 05:51 AM
Ohm`s law is for resistive loads, which cann`t applies to neither inductive or capacitive loads, such as motors, transformers

Properly, power is the dot product between voltage and current vectors, but is the magnitudes of the vectors multiplied by the cosine of the phase angle (often called power factor). For many small motors, power factor is quite close to 1 (especially when loaded) and is a reasonable approximation. Of course, if you know the power factor or phase angle, it should be used.

Unregistered
05-24-2010, 08:58 AM
I have a chart for a heat treat furnace that shows me at 10 second intervals, how many volts and amps I'm running. Can someone explain how I would convert this to KWH?

Ex:
5:06:00 Volts 5.279 Amps 1.7
5:06:10 Volts 5.279 Amps 1.7
5:06:20 Volts 22 Amps 433
5:06:30 Volts 18 Amps 306

Thanks!!

JohnS
05-24-2010, 12:49 PM
I have a chart for a heat treat furnace that shows me at 10 second intervals, how many volts and amps I'm running. Can someone explain how I would convert this to KWH?

Ex:
5:06:00 Volts 5.279 Amps 1.7
5:06:10 Volts 5.279 Amps 1.7
5:06:20 Volts 22 Amps 433
5:06:30 Volts 18 Amps 306

Thanks!!

For each 10 s sample, multiply the volts times the amps times the 10 seconds. The result will be a unit of energy known as the joule. (there will be a lot of joules).

3.6 MJ (mega joule or 3.6 million joules) = 1 kWh (comes from 1000 W times 3600 s/h)

Unregistered
05-25-2010, 02:20 AM
For each 10 s sample, multiply the volts times the amps times the 10 seconds. The result will be a unit of energy known as the joule. (there will be a lot of joules).

3.6 MJ (mega joule or 3.6 million joules) = 1 kWh (comes from 1000 W times 3600 s/h)

Thanks for the help!

JAScottContractors
09-18-2010, 09:57 AM
I have a customer trying to determine how much running her pond pumps is costing per month, doing an amp draw on the 2 circuits i get a total of 10.5 amps for both with voltage reading 122v on each leg. I did the rough conversion and im coming up with what seems extremely high numbers for a 30 day cycle running 24 hours a day. Am i missing something i have the power companies rate added up at .17380 cents KwH and end up showing over \$150 a month? :confused:

JohnS
09-18-2010, 10:48 AM
I have a customer trying to determine how much running her pond pumps is costing per month, doing an amp draw on the 2 circuits i get a total of 10.5 amps for both with voltage reading 122v on each leg. I did the rough conversion and im coming up with what seems extremely high numbers for a 30 day cycle running 24 hours a day. Am i missing something i have the power companies rate added up at .17380 cents KwH and end up showing over \$150 a month? :confused:

It looks about right. A few "picky" questions only because you are looking for something wrong:

*I'm a little confused by the two circuits, why is the load spread over two cirsuits? Are there two pumps, or pump and light? The two circuits aren't providing 240 V total are they?

But assuming data is correct, 10.5 A * 122 V = 1281 W = 1.281 kH
1.281 kW x 24 h/day x 30 day/month = 922 kWh/month
922 kWh/month x\$0.1738/kWh = \$160.30/month

*Do you have an instrument to measure power factor or phase angle between voltage and current. If not in phase, the power will be less than above. However, single phase motors usually aren't big reactive loads.

*What does the pump need to accomplish. If the motor is reasonably efficient, this is over 1 HP, and it should produce considerable flow and head. Does she need such a big pump (if it is powering a fountain, or lifting water back up for a waterfall, answer is probably)

JAScottContractors
09-19-2010, 10:12 AM
Yes its just the total amp load on two seperate single pole 20A breakers one side with a small filter pump has like a 1.5 amp load and the other breaker with the circulating pump, and arerator and a UV light has about 9amp load on it. The filter doesnt have a big head pressure on it the low pump which pumps back up to the top area has probably 12ft of vertical lift on about a 75ft horizontal run as the pond has several step downs for little waterfalls. But it is just two seperate 120v breakers feeding the two different areas. I just want to be sure because she rents the house and the landlord told her the pumps only cost around \$10-15 a month to run and im sure its way more then that i just am hesitant to say its \$150 a month i couldnt get to any of the motors as they are all submerged and landscaped in to a degree and shes not looking to make it cheaper to run she just wanted to know how much its costing her. Thanks again

JohnS
09-19-2010, 11:00 AM
Yes its just the total amp load on two seperate single pole 20A breakers one side with a small filter pump has like a 1.5 amp load and the other breaker with the circulating pump, and arerator and a UV light has about 9amp load on it. The filter doesnt have a big head pressure on it the low pump which pumps back up to the top area has probably 12ft of vertical lift on about a 75ft horizontal run as the pond has several step downs for little waterfalls. But it is just two seperate 120v breakers feeding the two different areas. I just want to be sure because she rents the house and the landlord told her the pumps only cost around \$10-15 a month to run and im sure its way more then that i just am hesitant to say its \$150 a month i couldnt get to any of the motors as they are all submerged and landscaped in to a degree and shes not looking to make it cheaper to run she just wanted to know how much its costing her. Thanks again

If she runs them 24/7, I think that is a reasonable cost estimate. If she runs the filter pump 24/7 and the big pump only for "decoration," it could be a lot lower depending on hours run. However, that might not give acceptable circulation between the various levels.

JAScottContractors
09-20-2010, 05:12 AM
If she runs them 24/7, I think that is a reasonable cost estimate. If she runs the filter pump 24/7 and the big pump only for "decoration," it could be a lot lower depending on hours run. However, that might not give acceptable circulation between the various levels.

Thank you very much:D

Unregistered
10-20-2010, 03:36 PM

Unregistered
11-11-2010, 09:10 AM
Need to convert 240/3 to 380/3

Unregistered
12-17-2010, 06:59 AM
i need to convert ampere of usage into kwh

900 amps to kwh

JohnS
12-17-2010, 10:29 AM
900 amps to kwh

Multiply by volts and hours to get watt-hours, divide by 1000 for kilowatt-hours.

Unregistered
06-14-2011, 05:51 PM
i need to convert ampere of usage into kwh

machine is using 45 amp , it is equivalent to how many kwh

JohnS
06-15-2011, 03:22 AM
machine is using 45 amp , it is equivalent to how many kwh

You also need the voltage, whether single or 3 phase, and the hours run.

1 A x 1 V = 1 W. If you draw 1 W for an hour, that is 1 Wh (a kWh is just 1000 Wh)

Unregistered
08-10-2011, 09:59 AM
converting amps to kwh requires multiple equasions, for example i will show the process for converting the amps used by a 100 watt bulb in a 115/120 volt powered circuit.
E=IxR states that volts are equivilent to amps X watts
So inversly volts divided by watts = amps
in this case 120 volts divided by 100 watts =1.2 amps
that given and adding that kwh=1000 watts used for 1 hr
so inversly a 1.2 amp load used continuosly for 1 hr = 100watt hours or 0.10kwh

I hope that helps

if P=IV then I = P/V

Deer hunter
08-11-2011, 05:42 PM
If i have a 3 phase motor with 460v and an average of 48.53amps running for 16 hours. How do i get the Kwh?

HerrWarum
08-11-2011, 06:02 PM
If i have a 3 phase motor with 460v and an average of 48.53amps running for 16 hours. How do i get the Kwh?
http://www.elec-toolbox.com/Formulas/Useful/formulas.htm

milchy25
08-24-2011, 01:33 AM
finally some smart guys that can help me.

i need your help people. I am building the mobile cart for coffee. and i want to be totally free of everything especially from the cable of electricity. So i will have 3kW generator, to fill the truck battery - 160 a/H, and from the battery convert energy (12v to 220V) to the espresso machine ( it needs 2,5kW to run). I need to know is this possible to make, will the generator run constantly or every now and then. If you have any other ideas to power espresso machine more efficiently please let me know.

Thank you guys very much in advanced.

JohnS
08-24-2011, 02:42 AM
finally some smart guys that can help me.

i need your help people. I am building the mobile cart for coffee. and i want to be totally free of everything especially from the cable of electricity. So i will have 3kW generator, to fill the truck battery - 160 a/H, and from the battery convert energy (12v to 220V) to the espresso machine ( it needs 2,5kW to run). I need to know is this possible to make, will the generator run constantly or every now and then. If you have any other ideas to power espresso machine more efficiently please let me know.

Thank you guys very much in advanced.

AT 100% efficiency (not really possible) to produce 2.5 kW, the inverter would draw 210 A from a 12 V battery or 105 A from a 24 V battery. If the expresso machine runs all the time, the generator needs to run all the time. It would be better to get a generator that produces 220 V and directly runs the expresso machine.

If the expresso machine only runs a few minutes, then is off for a while, it might make sense but you will need a large battery and a large inverter. You should fully discharge the 160 Ah battery if you want to get good life from it (no more than 50%). So fully charged, but only discharged to 80 Ah, it will only operate the expresso machine for less than 20 minutes.

Unregistered
08-31-2011, 08:11 AM
converting amps to kwh requires multiple equasions, for example i will show the process for converting the amps used by a 100 watt bulb in a 115/120 volt powered circuit.
E=IxR states that volts are equivilent to amps X watts
So inversly volts divided by watts = amps
in this case 120 volts divided by 100 watts =1.2 amps
that given and adding that kwh=1000 watts used for 1 hr
so inversly a 1.2 amp load used continuosly for 1 hr = 100watt hours or 0.10kwh

I hope that helps

============
The above is incorrect.

The correct equation is: kWh = volts*amps*hours/1000

Unregistered
09-05-2011, 12:01 PM
an infrared heater is 120 volt and is 1500 watts and draws 12.5 amps if it runs for one hour how many killowatts will it use

JohnS
09-05-2011, 12:45 PM
an infrared heater is 120 volt and is 1500 watts and draws 12.5 amps if it runs for one hour how many killowatts will it use

It uses 1500 W or 1.5 kW. In 1 hour, it will use 1.5 kWh
In 2 hours, it will use 3 kWh, and so on

Unregistered
09-07-2011, 07:45 AM
I have a pop machine operating at 120 volts drawing 11 amps, what is my conversion to kWh per hour?

JohnS
09-07-2011, 09:50 AM
I have a pop machine operating at 120 volts drawing 11 amps, what is my conversion to kWh per hour?

120 V x 11 A = 1320 W or 1.32 kW

In an hour, it will use 1.32 kWh, in two hours, 2.64 kWh

Kilowatt-hours are a unit of energy, the product of kilowatts (power) and hours (run time).

karla
09-18-2011, 12:05 PM
i need to convert 1.2 ampere of usage into kwh...

JohnS
09-18-2011, 12:24 PM
i need to convert 1.2 ampere of usage into kwh...

What is the voltage?
For how many hours of run time.

Unregistered
02-22-2012, 06:53 PM
i need to convert 250 ampere of usage into kwh

Unregistered
03-06-2012, 12:48 AM
Does the number of Phases have an effect on the consumption

Unregistered
07-24-2012, 09:55 AM
covert Kwh/kg to mAh/g

JohnS
07-24-2012, 10:09 AM
covert Kwh/kg to mAh/g

Multiply by 1000, divide by voltage.

kWh/kg is numerically equal to Wh/g
1 W = 1 A x 1 V, so divide by volts to get Ah/g
multiply by 1000 for mAh/g

Unregistered (Wayne)
08-17-2012, 04:14 AM
Hi, I stumbled across this searching Google.
Would I be right in thinking the following based on 3.3 amps, using 240v;
3.3x240=0.792kWh.
Assuming a cost of 0.043 per kWh, then 24 hours usage=0.81?
This seems quite low, so I'm not certain I have the right idea.

JohnS
08-17-2012, 09:46 AM
Hi, I stumbled across this searching Google.
Would I be right in thinking the following based on 3.3 amps, using 240v;
3.3x240=0.792kWh.
Assuming a cost of 0.043 per kWh, then 24 hours usage=0.81?
This seems quite low, so I'm not certain I have the right idea.

Numerically yes. Some minor units issues:
3.3 A x 240 V = 792 W or 0.792 kW, a unit of power.
A kilowatt for an hour, kWh, is a unit of energy.
0.792 kW x 24 h = 19 kWh (assuming it runs the full 24 h and current draw is constant)
19 kWh x \$0.043/kWh = \$0.817, call it \$0.82

Unregistered
09-02-2012, 08:07 PM
i want to use a 15kw/hr consuming machine on my single phase home line?will it work properly?plz reply soon.thanks.

JohnS
09-03-2012, 02:30 AM
i want to use a 15kw/hr consuming machine on my single phase home line?will it work properly?plz reply soon.thanks.

Maybe.

Is the machine wired for single phase, either 120 V or 240 V.
At 240 V, it consumes 62.5 A at 120 V, 125 A.
Do you have sufficient reserve in your electric wiring to support that plus normal loads?

It would certainly be better at 240 V, but you may need an electrician to bring in new power lines to your home, new meter and breaker box and wire in the machine.

Unregistered
10-11-2012, 06:06 AM
My Killowatt brand meter tells me that my CPAP (with humidifier) uses .18 to .22 kilowatts in a 7 hour period this is plugged into 115 volt single phase house current. I am wanting to use this in a small RV for remote camping and the power will be supplied from a pair of 6 volt golf cart batteries connected in series through a true sine wave inverter of about 300 watts (machine manufacturer says modified sine wave is not supported).

My goal is to determine how much power I will use for this machine. I understand that the inverter will introduce some losses and that there are other losses as well in the system.

Thanks!

Unregistered
10-12-2012, 07:49 AM
ineedto my moters powerin 2.25 kw and one moter is 0.75/1.0kw moters is 3phase what size stabeilizer need this is my ro plant howmuch kw wattes stabilizer need

Raja
03-23-2013, 12:53 AM
I have a motor drawing 4.7 amps at 120V. What is my kwh usage[/QUOTE]

P=V*I
=4.7*120=564W

If you are using for i hour

KWH=564*1/1000
= 0.564KWH

Unregistered
07-28-2013, 04:59 AM
I am looking at buying a 12/24/240v optional fridge/freezer the 40L model says it's power consumption is variable from 0.5-2.5 amps and uses 10.5kw per month.

The 80L model has the DC power consumption listed as variable from 0.5-4.2 amps using 12kw per month.

I would be looking at powering this with either a 12v 100 amp hour battery and running it as 12v or wiring two batteries together and running at 24v. I need to know how the power consumption will translate into drain on my battery over a 24 hour period in both scenarios.

Unregistered
08-16-2013, 11:02 AM
JohnS's answer is the best and is simple. Only one thing to nit-pick about, P = IV (Power - Current x Voltage) is for average power not instantaneous. Instantaneous power actually depends on where on the sine wave the voltage is at that instant. That formula is: P(instananious) = PMax * sin(2 pi f) * t. In radians.

Unregistered
09-02-2013, 09:57 AM
in 1 kw having 4 ampere

Unregistered
10-29-2013, 09:32 PM
I have a 70 watt HPS light which runs 5.5 hrs per day ,what is my KWH usage per day

JohnS
10-30-2013, 02:50 AM
I have a 70 watt HPS light which runs 5.5 hrs per day ,what is my KWH usage per day

70 W x 5.5 h/day x 1 kW/1000 W = 0.385 kWh/day

kevin
12-18-2013, 11:46 AM
i need to convert ampere of usage into kwh i have a samsung 4 how much will it cost me to have it on charge 8 hrs aday for a year?

Robert Fogt
12-18-2013, 10:24 PM
i have a samsung 4 how much will it cost me to have it on charge 8 hrs aday for a year?

This is not enough information, specifically what a samsung 4 is, how much power it uses, and how much you pay for your power.

Unregistered
01-04-2014, 06:38 PM
I have a motor drawing 4.7 amps at 120V. What is my kwh usage

i have a pump drawing that line current is 500amps and line voltage is 440 if load is 5 hours runnig then kwh=?

Unregistered
02-12-2014, 06:05 AM
Hi, my LG 55 inch led tv says its power requirements are 100-240V 50/60Hz 1.4A...

If the calculations using the formula in these thread were used, the power consumption is 308watts. My question is, if that is the true consumption, why does it say in its Specifications manual that the tv consumes only 53.9 watts when used and 0.3 watts when on standby? The TV is even certified as Energy Star qualified by the US EPA.

Can anyone pls enlighten me re these issues?

Btw, the voltage in our area is 220V. Thanks!

JohnS
02-12-2014, 06:51 AM
Hi, my LG 55 inch led tv says its power requirements are 100-240V 50/60Hz 1.4A...

If the calculations using the formula in these thread were used, the power consumption is 308watts. My question is, if that is the true consumption, why does it say in its Specifications manual that the tv consumes only 53.9 watts when used and 0.3 watts when on standby? The TV is even certified as Energy Star qualified by the US EPA.

Can anyone pls enlighten me re these issues?

Btw, the voltage in our area is 220V. Thanks!

The info isn't complete enough to say for sure, only guess:
1) The current rating is a maximum at probably occurs at the 100 V minimum. Regulated power supplies will generally draw less current with higher input voltages (the reverse of passive loads). It will draw much less at your 220 V. You can buy clamp-on or plug-in meters to measure this if you are really concerned.
2) Many newer TVs have variable levels of backlight brightness and automatically adjust to ambient room brightness. Again the 1.4 A is intended to be a maximum under worst case conditions. The specified power is probably under some Energy Star regimen of automated brightness adjustment. Certainly when the tv is "off" and only watching for signals from the remote, it is not drawing 1.4 A. The backlighting is a major power usage in a large TV

Unregistered
02-16-2014, 07:11 PM
The info isn't complete enough to say for sure, only guess:
1) The current rating is a maximum at probably occurs at the 100 V minimum. Regulated power supplies will generally draw less current with higher input voltages (the reverse of passive loads). It will draw much less at your 220 V. You can buy clamp-on or plug-in meters to measure this if you are really concerned.
2) Many newer TVs have variable levels of backlight brightness and automatically adjust to ambient room brightness. Again the 1.4 A is intended to be a maximum under worst case conditions. The specified power is probably under some Energy Star regimen of automated brightness adjustment. Certainly when the tv is "off" and only watching for signals from the remote, it is not drawing 1.4 A. The backlighting is a major power usage in a large TV

Do you mean sir that the power consumption would be less if I use the 220V assuming I'll use the LED TV normally and with backlighting to a minimum? I don't need to use a Voltage regulator to utilize a 120V outlet conversion from 220? I ask this bec when you get the wattage consumption from 120V x 1.4A, I'll get a lower wattage figure than a 220V.

Thanks sir.

JohnS
02-17-2014, 02:54 AM
Do you mean sir that the power consumption would be less if I use the 220V assuming I'll use the LED TV normally and with backlighting to a minimum? I don't need to use a Voltage regulator to utilize a 120V outlet conversion from 220? I ask this bec when you get the wattage consumption from 120V x 1.4A, I'll get a lower wattage figure than a 220V.

Thanks sir.

It depends on the design so you would have to measure to be sure. However, for modern design, I would expect it to draw about half the current at 220 V as it does at 110, ie, the power consumption is approximately constant with the two input voltages. Reducing brightness of the backlight will certainly reduce power.