Need to know how many acres I have

[Derinda Heaps]

My piece of land is 150 x 150 x 150 x 150. How many acres do I have

[brenett66]

150 x 150 x 150 x 150 what measurements meter feet yards

[Robert Fogt]

150 units * 150 units = 22500 square units

if the unit is feet, then the result is square feet, if the unit is meters then the result is square meters, etc.

You can use the area conversion page to convert square somethings to acres.

I will guess and say its feet, and 22500 square feet is about 1/2 an acre.

[Unregistered]

150 units * 150 units = 22500 square units

if the unit is feet, then the result is square feet, if the unit is meters then the result is square meters, etc.

You can use the area conversion page to convert square somethings to acres.

I will guess and say its feet, and 22500 square feet is about 1/2 an acre.
If I have 250 ft. in road frontage, how far must I go back in feet to get 5 acres?

[brenett66]

250 X 871.2 = 217800 square feet = 5 acres

[Robert Fogt]

I now have a calculator that can do this.

http://www.onlineconversion.com/shape_area_rectangle.htm

Enter 217,800 for the area, 250 for the length, and it calculates the width. (also the perimeter).

[Unregistered]

how many foots have one acre

[ajp2856]

my land is 3000 x 3000 x 3800 x 3800 how many acres do I have

[Unregistered]

250 x 1000 = acres

[Unregistered]

250 x 150 feet = acres?

[Unregistered]

if you calculate your area in Square feet and divide the result of that by 43,560, you will have the acreage

in case you dont know, area = Length x Width

[Unregistered]

my land is 430 x 355 x 771 x 565 feet can you please fiure the Acrage out for me ty

[HerrWarum]

my land is 430 x 355 x 771 x 565 feet can you please fiure the Acrage out for me ty
". . .a four-sided figure, it can't be larger than a square with the same perimeter"
There may also be a formula for the minimum area enclosed by a four sided figure.

[JohnS]

". . .a four-sided figure, it can't be larger than a square with the same perimeter"
There may also be a formula for the minimum area enclosed by a four sided figure.

A tighter upper bound comes from Breitschneider's formula when opposite angles add to 180°. For four sides, a, b, c, d, compute
s =(a+b+c+d)/2
A = sqrt((s-a)*(s-b)*(s-c)*(s-d))

For a lower bound the figures can be flexed to form four degenerate triangles two where sides add (an angle goes to 180°) and two where sides subtract (an angle goes to 0°). The additive ones are the limits when maintaining a convex shape, the subtractive ones are the extreme limit of one vertex being concave (lies inside diagonal from adjacent vertices). Solve the triangles by Heron's formula. Pick the lower of the two convex cases if the figure at least remains convex, or the lower of the two concave figures otherwise.

Calculating the worst case triangles is a bit of a PITA. I have fairly high confidence in the following rules, but haven't proved them yet. Identify the shortest and longest side, s and l. Let the other two be p and q.
1) If s + l = p + q, the figure collapses entirely and min area is zero.
2) If s + l > p + q, location of shortest side doesn't matter, denote the side opposite the longest side as opp. Then the convex limits come fom considering the two cases of opp+adj forming a 180° angle, and the concave limits from two cases of l - adj forming a 0° angle.
3) If s + l < p +q, then rules differ depending on whether s is opposite or adjacent to l.
3a) s is opposite l. Convex: adj + s, concave: adj - s
3b) s adjacent to l. Convex: opp + s, l +s, concave: opp - s, l - s

For the given quadralateral, minimum concave area is 36333 ft², min. convex area is 119100 ft² and max area is 252602 ft².

Without angular info (or a diagonal) we don't know much about it at all.

[Unregistered]

how many square in 1.2 acres

[Unregistered]

how many square in 1.2 acres

[JohnS]

how many square in 1.2 acres

1.2 acre x 43560 ft²/acre = 52272 ft²