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Unregistered
10-12-2009, 08:04 AM
A lab technician places a 5.00g food ssample into a bomb calorimeter that is calibrated at 9.23 kj/C (thats suppsed to be over degrees celcius) The initial temperature of the calorimeter systme is 21.0C. After burning the food the final temperature of the system is 32.0C.. What is theheat combustion of the food?

JohnS
10-12-2009, 10:06 AM
A lab technician places a 5.00g food ssample into a bomb calorimeter that is calibrated at 9.23 kj/C (thats suppsed to be over degrees celcius) The initial temperature of the calorimeter systme is 21.0C. After burning the food the final temperature of the system is 32.0C.. What is theheat combustion of the food?
So the temperature change is 11 degrees, and you have the calibration constant. I think it is just 101.5 kJ.

Unregistered
10-12-2009, 10:12 AM
Thank You very much John!!

Unregistered
10-12-2009, 10:24 AM
Can I get the formula used to get this, so I can figure out the future problems...thanx again!!!

Unregistered
10-12-2009, 10:30 AM
I wanna use the nH=cdeltat formula... but I can't convert the food grams to moles.... so it won't work for my n value

JohnS
10-12-2009, 11:23 AM
Can I get the formula used to get this, so I can figure out the future problems...thanx again!!!

The temperature difference is just the final minus initial temperature, and the heat of combustion is the calibration constant times the temperature difference.